原题:
实现代码:
#include;int main() { int n; int step = 0; scanf("%d", &n); while (n != 1) { if (n % 2 == 0) { n = n / 2; step++; } else { n = ((3 * n) + 1) / 2; step++; } } printf("%d", step); return 0;}
本文共 352 字，大约阅读时间需要 1 分钟。
原题:
实现代码:
#include;int main() { int n; int step = 0; scanf("%d", &n); while (n != 1) { if (n % 2 == 0) { n = n / 2; step++; } else { n = ((3 * n) + 1) / 2; step++; } } printf("%d", step); return 0;}
转载于:https://www.cnblogs.com/asheng2016/p/7637778.html